Question

if P bracket x is equal to 4 x power 5 minus 3 x power 4 minus 5 x cube + x cube minus 8 then find P bracket minus one​

Answer 1

SOLUTION

GIVEN

$\sf{P(x) = 4 {x}^{5} - 3 {x}^{4} - 5 {x}^{3} + {x}^{2} - 8 }$

TO DETERMINE

The value of P(-1)

EVALUATION

Here the given polynomial is

$\sf{P(x) = 4 {x}^{5} - 3 {x}^{4} - 5 {x}^{3} + {x}^{2} - 8 }$

Putting x = - 1 we get

$\sf{P( - 1) = 4 {( - 1)}^{5} - 3 {( - 1)}^{4} - 5 {( - 1)}^{3} + {( - 1)}^{2} - 8 }$

$\sf{ \implies \: P( - 1) = - 4 - 3 + 5 + 1 - 8 }$

$\sf{ \implies \: P( - 1) = - 15 + 6 }$

$\sf{ \implies \: P( - 1) = -9 }$

FINAL ANSWER

$\sf{ P( - 1) = -9}$

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