Question

The two equal sides of an isosceles triangle are taken as y cm and unequal sideis taken as x cm. Find its perimeter in termsof x and y.

Answer 1

$\mathfrak{\blue{\underline{\underline{Answer}}}}$

$\boxed{(2y + x)cm}$

$\mathfrak{\blue{\underline{\underline{Step \:by\: Step \:Solution}}}}$

Given:

An Isosceles Triangle

Length of each of the two equal sides (in centimetre) = x

Length of unequal side (in centimetre) = y

Let the triangle be $\triangle ABC$

Where, two equal sides are AB and AC

Unequal side is BC

Here,

AB = AC = y

BC = x

We know,

$\boxed{Perimeter\: of\: Triangle = Sum\: of\: all\: sides}$

So,

Perimeter of $\triangle ABC$ = AB + AC + BC

Perimeter of $\triangle ABC$ = y + y + x

Perimeter of $\triangle ABC$ = 2y + x

Answer 2

HEre Is Your Ans ⬆⤵

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Let , Δ ABC Be The Isosceles Triangle

According To The Question ,

AB = AC = Y cm And BC = X cm

➡Perimeter of Δ ABC = AB + BC + AC

➡Perimeter of Δ ABC = Y + X + Y

➡Perimeter of Δ ABC = 2Y + X

Hence , Perimeter Of Isosceles Triangle in terms of X and Y Is $\fbox{2Y + \: X }$

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