Math, asked by bhavya7208, 10 months ago

If P divides seg AB in ratio AP : PB = 2 : 1 , then PB is ____ part of AB.

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Answered by Anonymous
1

Answer:

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8th

Maths

Mensuration

Area of Trapezium

In ABC, P divides the sid...

MATHS

In △ ABC, P divides the side AB such that AP:PB = 1 : 2. Q is a point in AC such PQ∥BC. Find the ratio of the area of △ APQ and trapezium BPQC.

December 27, 2019avatar

Tanish Thakur

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ANSWER

If a line is drawn parallel to one side of a triangle to intersect the

other two sides in distinct points, the other two sides are divided in the same ratio.

As PQ∥BC

So

PB

AP

=

QC

AQ

∠AQP=∠ACB

∠APQ=∠ABC

So by AAA △AQP∼△ACB

The ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides.

Hence

Area(ABC)

Area(APQ)

=

(AB)

2

(AP)

2

Area(ABC)

Area(APQ)

.plede mark brainlist answer

=

(AP+PB)

2

(AP)

2

Area(ABC)

Area(APQ)

=

(3x)

2

(x)

2

Area(ABC)

Area(APQ)

=

9

1

Let Area(APQ)=k

Area(ABC)=9k

Area(BPQC)=Area(ABC)−Area(APQ)=9k−k=8k

Area(BPQC)

Area(APQ)

=

8

1

∴ the ratio of the △APQ and trapezium BPQC =

8

1

Answered by Anonymous
3

Answer:

Hey DEAR 4:3 is your answer

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