Question

If P(E) = 0.008, what is the probability of “not E” ?​

Answer 1

Answer:

0.992

Step-by-step explanation:

p(e)+p (not e) always equals to 1

and hence,

0.008+p(not e)=1

p(not e)=1-0.008

p(not e)=0.992

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Answer 2

Given : P(E) = 0.008

To Find :  probability of “not E”

Solution:

P(E) = 0.008

=> Probability of occurring of event E  = 0.008

For any event

Probability of Occurring + Probability of not occurring = 1

also probability of an event always lies between 0 and 1 ( including both )

Hence

P ( E)  + P ( not E)  = 1

=> 0.008  + P ( not E)  = 1

=> P ( not E)  = 1  - 0.008

=>  P ( not E)  = 0.992

probability of “not E”  is 0.992

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