Math, asked by sPari11, 1 year ago

if p(e)=0.02 then what is the probability of not E

Answers

Answered by sallukhan
15
p(e ) + p(not e ) = 1

p( not e) =1 - p(e) = 1 - 0.02 = 0.98
Answered by pulakmath007
1

If P(E) = 0.02 then the probability of not E is 0.98

Given :

P(E) = 0.02

To find :

The probability of not E

Solution :

Step 1 of 2 :

Write down the given probability

Here it is given that for the event E

P(E) = 0.02

Step 2 of 2 :

Find probability of not E

We know that for any event E ,

P(E) + P(not E) = 1

In order words P(E) + P(E') = 1

Thus we get

P(E) + P(not E) = 1

⇒ 0.02 + P(not E) = 1

⇒ P(not E) = 1 - 0.02

⇒ P(not E) = 0.98

Hence the required probability of not E = 0.98

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