if p(e)=0.02 then what is the probability of not E
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p(e ) + p(not e ) = 1
p( not e) =1 - p(e) = 1 - 0.02 = 0.98
p( not e) =1 - p(e) = 1 - 0.02 = 0.98
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If P(E) = 0.02 then the probability of not E is 0.98
Given :
P(E) = 0.02
To find :
The probability of not E
Solution :
Step 1 of 2 :
Write down the given probability
Here it is given that for the event E
P(E) = 0.02
Step 2 of 2 :
Find probability of not E
We know that for any event E ,
P(E) + P(not E) = 1
In order words P(E) + P(E') = 1
Thus we get
P(E) + P(not E) = 1
⇒ 0.02 + P(not E) = 1
⇒ P(not E) = 1 - 0.02
⇒ P(not E) = 0.98
Hence the required probability of not E = 0.98
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