Question

If p (e)=0.04,what is the probability of not e?

Answer 1

Step-by-step explanation:

We know that the sum of the probabilities of all the elementary events of an experiment is 1.

If an experiment has two elementary events say E & not E then,

P(E)+P(notE)=1⟹P(notE)=1−P(E)

Given P(E)=0.05

∴P(notE)=1−0.05=0.95

Answer 2

If P(E) = 0.04 then the probability of not E is 0.96

Given :

P(E) = 0.04

To find :

The probability of not E

Solution :

Step 1 of 2 :

Write down the given probability

Here it is given that for the event E

P(E) = 0.04

Step 2 of 2 :

Find probability of not E

We know that for any event E ,

P(E) + P(not E) = 1

In order words P(E) + P(E') = 1

Thus we get

P(E) + P(not E) = 1

⇒ 0.04 + P(not E) = 1

⇒ P(not E) = 1 - 0.04

⇒ P(not E) = 0.96

Hence the required probability of not E = 0.96

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