Question

If P(e) = 0.05 what is the probability of not'e'

Answer 1

Answer:

P (e)=0.05

Probability of not 'e'=P'(e)

Now,

P (e)+P'(e)=1

P'(e)=1-P (e)

=1-0.05

=0.95

Answer 2

$here \: is \: your \: answer \: mate \:$

we know that p(e) + p(not e) = 1

therefore p(not e) = 1 - p(e)

here , p(e) = 0.05

= 0.95

the probability of (not e) = 0.95

$hope \: it \: is \: helpful \: for \: u$