If P(E)=0.05, what is the probability of 'Not E'?
Answers
Answered by
362
we know,
P(E) + P( not E) = 1
here, P(E) = 0.05
0.05 + P(not E) = 1
P(not E) = 1 -0.05 = 0.95
P(E) + P( not E) = 1
here, P(E) = 0.05
0.05 + P(not E) = 1
P(not E) = 1 -0.05 = 0.95
Answered by
413
We know that The probability of any thing happening guarantedly is 1
and sum of probabilities of All events is 1
P ( E) + P ( not E) = 1
P ( not e) = 1 - P ( E)
= 1-0.05
= 0.95
The probability of ' Not E " is 0.95
and sum of probabilities of All events is 1
P ( E) + P ( not E) = 1
P ( not e) = 1 - P ( E)
= 1-0.05
= 0.95
The probability of ' Not E " is 0.95
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