Question

If
P(E)
0.54
then find P(nAE)
​

Answer 1

probability of an event is 0.54

than,

it will be subtracted from 1 according to the formula

p(e)=1-p(e)

p(e)=1-0.54

p(e)=0.46

therefore the probability of an event is 0.46(answer).

Answer 2

Step-by-step explanation:

Using the relations :

( a ) P( A U B ) = P( A ) + P( B ) - P( A ∩ B )

( b ) P( A' ∩ B') = P(A U B)' = 1 - P( A U B )

( c ) P( A ∩ B') = P( A ) - P( A ∩ B)

( d ) P( B ∩ A') = P( B ) - P( B ∩ A)

Here, P( A ) = 0.54 , P( B ) = 0.69

P( A ∩ B ) = 0.35

(i) P( A U B ) = P( A ) + P( B ) - P( A ∩ B )

= 0.54 + 0.69 - 0.35

= 1.23 - 0.35

= 0.88

( ii) P( A' ∩ B') = P(A U B)' = 1 - P( A U B )

= 1 - 0.88

= 0.12

(iii) P( A ∩ B') = P( A ) - P( A ∩ B)

= 0.54 - 0.35

= 0.19

( iv) P( B ∩ A') = P( B ) - P( B ∩ A)

= 0.69 - 0.35

= 0.34