if P is a point on side BC of a triangle
prove that in ∆ABC ,
AB +BC +AC >2AP
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Step-by-step explanation:
In ABP
AB+BP+AP=180
IN APC
AP+PC+AC=180
THEREFORE
AB+BP+AP=AP+PC+AC
=AB+BP+PC+AC=AP+AP
=AB+BC+AC=2AP
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