if p is a zero of 2x^2-5x+3,then find the value of p
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Answered by
2
the factors of 3 May be +-1,+-2,+-3
by putting x=1 , we get
2(1)^2 - 5(1)+ 3
2-5+3
5-5
therefore, p= 0
by putting x=1 , we get
2(1)^2 - 5(1)+ 3
2-5+3
5-5
therefore, p= 0
KSAISHWARYAHOYSAL:
mmmmm.
Answered by
0
Answer:
The value of p is either 1 or 3/2, here's how;
Step-by-step explanation:
let p(x) = 2x^2 -5x +3
(using the splitting middle term method)
p(x) = 2x^2 -5x +3
p(x) = 2x^2 -2x -3 +3
p(x) = 2x(x-1) -3(x-1)
p(x) = (x-1) (2x-3)
x-1
x = 1
and
2x-3
2x = 3
x = 3/2
thus the zeros of p(x) are 1 and 3/2
hence we can say that the value of p can be either 1 or 3/2
^o^
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