if P is equal to 2 - a prove that a cube + 6ap + p cube minus 8 is equal to zero
Answers
Answered by
8
Answer:
Step-by-step explanation:
Given:
If P is equal to 2 - a prove that a cube + 6ap + p cube minus 8 is equal to zero
Soluttion:
p = 2 - a -------( 1 )
LHS = a³ + 6ap + p³ - 8
= a³ + 6a( 2 - a ) + ( 2-a )³ - 8 [ from(1)]
= a³ +12a-6a²+2³-3×2²a+3×2a²-a³-8
= a³ + 12a - 6a² + 8 - 12a + 6a²- a³ - 8
= 0
= RHS
Hence proved.
Similar questions