Question

If P is in equillibrium, then tensions \frac{T_{1}}{T_{2}}= T 2 ​ T 1 ​ ​ = 1 2 2 \frac{1}{\sqrt{3}} 3 ​ 1 ​ 3 \sqrt{3} 3 ​ 4

Answer 1

Answer:

Comparing (1) and (2) gives A_{n}=\frac{-2L}{ n\pi }B_{n} ... ( n\frac{\pi }{L}t\right ) dt\\ & =L^{2 }\left ( t\right ) _{0}^{x}+3\sum _{n=1}^{\infty }