if P is the momentum of the fastest electron ejected from a metal surface after theirradiation of Light having wavelength Lambda then for 1.5 the momentum of the photoelectron the wavelength of the light should be
Answers
Answered by
0
Answer:
Lambda = h/mv
= h/p
= 6.626 *10^-34/1.5
=4.417*10^-34 m
Explanation:
hope it is the ANS
Similar questions
Science,
5 months ago
Computer Science,
5 months ago
Science,
5 months ago
Computer Science,
11 months ago
Math,
11 months ago