Chemistry, asked by yasserasaad0204, 11 months ago

if P is the momentum of the fastest electron ejected from a metal surface after theirradiation of Light having wavelength Lambda then for 1.5 the momentum of the photoelectron the wavelength of the light should be​

Answers

Answered by physisit
0

Answer:

Lambda = h/mv

= h/p

= 6.626 *10^-34/1.5

=4.417*10^-34 m

Explanation:

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