Question

if p(m)=m^2-3m+1, then find the value of p(1) andp(-1).​

Answer 1

Answer:

$\huge \underline \mathbb {answer:-}$

ANSWER

The polynomial

p(m)=m2−3m+1

p(1)=12−3(1)+1=1−3+1=−1

p(−1)=(−1)2−3(−1)+1+3+1=5

p(1)=−1 and p(−1)=5

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Answer 2

Answer:

p(1)= -3

&. p(-1)=5

Step-by-step explanation:

p(m) = m^2-3m+1

p(1) = (1)^2-3(1)+1

=. 1-3+1

p(1) = -3

p(-1) = (-1)^2-3(-1)+1

= 1+3+1

p(-1) = 5

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