If P(m) = m2
– 3 m + 1, then find P(1) + P(–1)
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Given :
- P(m) = m² – 3m + 1
To find :
- P(1) + P(–1)
Solution :
To find the value of P(1) + P(–1) first we have to find the value of P(1) and P(–1).
⟹ To find the value of P(1) first put m =1 in P(m) = m² – 3m + 1
⟹ P(1) = (1)² – 3(1) + 1
⟹ P(1) = 1 – 3 + 1
⟹ P(1) = 2 – 3
⟹ P(1) = -1
⟹ To find the value of P(-1) first put m =1 in P(m) = m² – 3m + 1
⟹ P(-1) = (-1)² – 3(-1) + 1
⟹ P(-1) = 1 + 3 + 1
⟹ P(-1) = 2 + 3
⟹ P(-1) = 5
Now , we have to find P(1) + P(–1) :-
⟹ P(1) + P(–1)
⟹ -1 + 5
⟹ 4
Answer :
P(1) + P(–1) = 4
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