Question

If P = maximum value of sin α and Q = maximum value of cos β, then find the value of 6P – 3Q.​

Answer 1

Answer:

3

Step-by-step explanation:

maximum value of sin α is 1

maximum value of cos β is also 1

therefore: 6P= 6(1) = 6 and

3Q = 3(1) = 3

so, 6P - 3Q = 6-3 = 3