Question

If p(n,2)=72,find the value of n​

Answer 1

Step-by-step explanation:

We know, P(n, 2) = n * (n-1) * (n-2) * ----- 3*2*1/ (n-2)*(n-3)* ----------- *3*2*1

So, we get P(n,2) = n (n-1), which is given = 72

or, n^2-n = 72

or n^2 - n -72 = 0

or n^2 - 9n +8n -72 = 0

or n(n-9)+8(n-9) = 0

or, (n-9) (n+8) = 0

so, n being a natural number n-9 = 0

n = 9

Answer 2

Answer:

pn,2=72

Step-by-step explanation: