Question

if p(n)= 5-4x+2x^2,find p(a),p(3),p(-2)​

Answer 1

Step-by-step explanation:

P(1)=5-4+2

=3

p(0)=5-0-0

=5

p(2)=5-8+8

=5

p(3)=5-12+18

=11

p(-2)=5+8+8

=21

Answer 2

Answer:

P(X) = 5-4X+2X² => 2X²-4X+5

P(0) = 2 × (0)² - 4 × 0 +5 = 0-0+5 = 5

P(3) = 2 × (3)² - 4 × 3 +5 = 2 × 9 -12 +5 = 18-12+5 = 11

P(-2) = 2 × (-2)² - 4 × -2 + 5 = 2 × 4 +8 +5 = 8+8+5 = 21.    

therefor,

P(0) = 5 , P(3) = 11 AND P(-2) = 21.