Question

if p+q = 12 and pq=22,find p^2+q^2​

Answer 1

Answer:

(p+q)² = p² + q² + 2pq

12² = p² + q² + 2 × 22

p² + q² = 144-44

= 100

Answer 2

Answer:

$\large\bold\red{100}$

Step-by-step explanation:

Given,.

$p + q = 12$

And,

$pq = 22$

To find the value of,

${p}^{2} + {q}^{2}$

We know that,

${(p + q)}^{2} = {p}^{2} + {q}^{2} + 2pq$

Substituting the values,

We get,

$= > {(12)}^{2} = {p}^{2} + {q}^{2} + 2 \times 22 \\ \\ = > {p}^{2} + {q}^{2} + 44 = 144 \\ \\ = > {p}^{2} + {q}^{2} = 144 - 44 \\ \\ = > {p}^{2} + {q}^{2} = 100$

Hence,

Tge required answer is 100.