Question

If p+q=12, and pq=22, find p^2+q^2.

Answer 1

Given,

$\rm{}p+q=12 \\ \rm\: \: \: \: \: \: pq = 22$

Now,

$= > \rm {(p + q)}^{2} = {(12)}^{2} \\ \rm = > {p}^{2} + {q}^{2} + 2pq = 144 \\ \rm = > {p}^{2} + {q}^{2} = 144 - 2pq \\ \sf = > {p}^{2} + {q}^{2} = 144 - 2(22) \\ \sf= > {p}^{2} + {q}^{2} = 144 - 44 \\ \sf = > {p}^{2} + {q}^{2} = 100$

Answer 2

Answer:

hope it is helping you dear

marks me as brilliant and follow me