Question

if p+q=13 and pq=22, then p^2+q^2=?​

Answer 1

Step-by-step explanation:

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Answer 2

ANSWER:

• Value of p²+q² is 125.

GIVEN:

• p+q = 13
• pq = 22 ......(i)

TO FIND:

• Value of p²+q².

SOLUTION:

=> p+q = 13

Squaring both sides:

=> (p+q)² = (13)²

=> p²+q²+2pq = 169

=> p²+q²+2(22) = 169 [From eq (i)]

=> p²+q²+44 = 169

=> p²+q² = 169-44

=> p²+q² = 125

Value of p²+q² = 125.

NOTE:

Some important formulas:

(a+b)² = a²+b²+2ab

(a-b)² = a²+b²-2ab

(a+b)(a-b) = a²-b²

(a+b)³ = a³+b³+3ab(a+b)

(a-b)³ = a³-b³-3ab(a-b)

a³+b³ = (a+b)(a²+b²-ab)

a³-b³ = (a-b)(a²+b²+ab)

(a+b)² = (a-b)²+4ab

(a-b)² = (a+b)²-4ab