If p/q= (4/9)^(-3)÷(4/9)^(-2), find(p/q)^(-1)÷(q/p)^(-1)
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Answered by
8
P/q=(4/9)^(-3) ÷ (4/9)^(-2)
p/q=(9/4)^3 ÷ (9/4)^2
p/q=(9/4)
(p/q)^(-1)=4/9
(q/p)^(-1)=9/4
according to question
(p/q)^(-1)÷(q/p)^(-1)=16/36=4/9
p/q=(9/4)^3 ÷ (9/4)^2
p/q=(9/4)
(p/q)^(-1)=4/9
(q/p)^(-1)=9/4
according to question
(p/q)^(-1)÷(q/p)^(-1)=16/36=4/9
kaushikravikant:
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Answered by
2
given p/q=(4/9)^-3÷(4/9)^-2
p/q=(9/4)^3÷(9/4)^2
p/q=9/4
q/p=4/9
now we have to find
(p/q)^-1÷(q/p)^-1
=(q/p)^1÷(q/p)^-1
=(q/p)^2
=(4/9)^2
=16/81
p/q=(9/4)^3÷(9/4)^2
p/q=9/4
q/p=4/9
now we have to find
(p/q)^-1÷(q/p)^-1
=(q/p)^1÷(q/p)^-1
=(q/p)^2
=(4/9)^2
=16/81
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