If ∠P-∠Q=42° , ∠Q-∠R=21° then find the value of ∠P , ∠Q , ∠R when PQR is a triangle.
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P-Q=42° eqn-1
Q-R=21° eqn-2
THEN,
P=42+Q
and
R=Q-21
in∆PQR
P+Q+R=180° eqn-3
now, putting value of P and R in eqn-3,we get.
42+Q+Q+Q-21=180
=>3Q+21=180
=>3Q=180-21=159
=>Q=53°
PUTTING VALUE OF Q IN EQN-1 AND 2
WE GET,
P-Q=42
=> P=42+Q=42+53=95°
and,
Q-R=21
=>R=Q-21=53-21=32° Ans.
Hope You understand it well...
HAPPY TO HELP✌️
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