If p+q=5 prove p^3 +q^3 +15pq=125
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Given:
↬ p+q= 5
To Prove:
✏ p³+q³+15pq= 125
Solution:
We know that,
⟼ (a+b)³ =a³ +b³ +3ab(a+b)
⟼ 5³ = 125
It is given that
➺ p+q= 5
On cubing both the sides, we get
➺ (p+q)³= 5³
➺ p³+q³+3(p)(q)(p+q)= 125
➺ p³+q³+3pq(p+q)= 125
On putting the value of p+q, we get
➺ p³+q³+3pq(5)= 125
➺ p³+q³+15pq= 125
Hence proved
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