Question

If p-q=7 and pq=18, then find the value of p^2-q^2​

Answer 1

Answer:

hi friends. so first, let us recollect factors of 18. 1x18. 2x9. 3x6. that is it. so in all these factors 9x2 is suitable. let us check it out. 9-2=7.

Missing: then ‎| Must include: then

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2*9=18 AND 9-2=7 SO THAT P=9 AND Q=2P+Q=9+2=11 PLEASE MARK ME AS BRAINLIEST More

Answer 2

Answer:

The correct answer is 77....

Step-by-step explanation:

Given, p - q = 7 and pq = 18

So, (p-q)² = (7)²

p² - 2pq + q² = 49

p² + q² = 49 + 2(18)

p² + q² = 85

Now, (p+q)² = p² + 2pq + q²

(p+q)² = p² + q² + 2(18)

(p+q²) = 85 + 36

(p+q)² = 121

p+q = 11...[As 11² = 121]

Now, (p+q)(p-q) = p² - q²

(11)(7) = p² - q²

p² - q² = 77