if p,q amd r are three consecutive terms of an AP whose common is d , then the value of r - p is
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Answer:
Recall that an arithmetic sum is the product of the average of its first and last term and the number of terms.
Here p and r are the first and last terms respectively and there are three terms.
The average of the first and last terms is (p+r)/2. But note that the ratio indicates that p=6r. Therefore a substitution can be made so that the avg becomes 7r/2. There are three terms so multiply by 3, and the sum becomes 21r/2. The given sum is 21, allowing us to solve for r.
Using the fact that r=2, we can determine p using the same formula for the sum. When the equation is solved, p=12. Using the fact that they are two common differences apart, you can deduce that q=7.
Finally: p=12, q=7, and r=2.
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