Question

if | p | = | q | and angle between vector p and vector q is neither zero nor 180° then what is the angle between (p+q) and (p-q) ... p nd q are vectors​

Answer 1

Answer:

90 degrees.

Explanation:

Angle relation between (p+q) and (p-q) using dot product,

(p+q).(p-q) = |(p+q)| |(p-q)| cosθ

$\\\tt p^2 - q^2 = |\sqrt{p^2 + q^2} ||\sqrt{p^2 + q^2} | \cos\theta\\\\\tt 0 =( p^2 + q^2 ) \cos\theta\\\\\tt \cos\theta = 0 \\\\\tt \theta = 90^{\circ}$