If p,q and r are in AP,then prove that (p+2q-r)(2q+r-p)(r+p-q) = 4pqr
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Heyy mate ❤✌✌❤
Here's your Answer....
⤵️⤵️⤵️⤵️⤵️⤵️⤵️
Since, They are in same A.P.
Therefore, Common Difference (d) will be same .
=> q - p = r - q
=> 2q = r + p
Now,
=> (p + 2q+ r) (2q+r-p)(r+p-q)
=>(p + r + p- r) ( r + p + r -p) ( r+ p- q)
=> (2p) × 2r × ( 2q - q)
=> 2p × 2r × q
=> 4pqr.
✔✔✔
Here's your Answer....
⤵️⤵️⤵️⤵️⤵️⤵️⤵️
Since, They are in same A.P.
Therefore, Common Difference (d) will be same .
=> q - p = r - q
=> 2q = r + p
Now,
=> (p + 2q+ r) (2q+r-p)(r+p-q)
=>(p + r + p- r) ( r + p + r -p) ( r+ p- q)
=> (2p) × 2r × ( 2q - q)
=> 2p × 2r × q
=> 4pqr.
✔✔✔
mitalisingh802:
Thanks yr
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