Question

If p ,q and r are zeroes of polynomial 6x³+3x²−5x+1, then the value of 1/p + 1/q + 1/r =

Answer 1

Here is the answer...
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Answer 2

Answer:

(1/p)+(1/q)+(1/r)=5

Step-by-step explanation:

Here a=6, b=3, c= -5, d=1

Now

Product of roots p×q×r=(-d/a)

Sum of the product of roots i.e

pq+qr+rp=(c/a)

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