Question

if p,q are roots of x^2+px+q=0 p,q=?

Answer 1

Product of zeroes = c/a
pq = q
p = 1

Sum of zeroes = -b/a
p+q = -p
q = 2p
q = 2×1
q = 2

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Answer 2

SOLUTION :  

Option (a) is correct : p = 1 ,q = - 2

Given : ‘p’ & 'q’ are the roots of the equation x² - px + q = 0

On comparing the given equation with ax² + bx + c = 0  

Here, a = 1 , b = - p  , c = q

Sum of zeroes = - b/a  

p + q  = - b/a

p + q  = - p/1

p + q  = - p

q = - p - p

q = - 2p ………..(1)

Product of zeroes = c/a  

p × q = c/a

pq = q/1

p = q/q

p = 1

On putting the value of p = 1 in eq 1

q = - 2p

q = - 2(1)

q = - 2

Hence, the value of p is 1 & q = - 2.

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