Question

If p, q are the zeroes of 2x2

– 6x + 3, then find the value of (p3

+ q3) – 3pq(p2+ q2) – 3pq(p + q).​

Answer 1

Answer:

-27

Step-by-step explanation:

$2x^{2} -6x + 3$ is the given equation

p and q are the zeroes therefore

p + q = -(-6)/2=3

and pq = 3/2

$p^{3}+q^3 -3pq(p^2+q^2)- 3pq(p+q)$ =

$[(p+q)^3 - 3pq(p+q)] - 3pq[(p+q)^2 - 2pq] -3pq(p+q)$

substituting the values of (p +q) and (pq)

we get

-27 as the answer

Thank You!!