If P ,Q are the zeros of the quadratic polynomial ( 4x^2 - 4x + 1 ) then ( P^3. + Q^3 ) is
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Given:
P , Q are the zeroes of 4x² - 4x + 1.
On comparing with standard form of a quadratic equation i.e., ax² + bx + c
Let,
- a = 4
- b = - 4
- c = 1.
We know that,
Sum of the zeroes = - b/a
⟶ P + Q = - ( - 4)/1
⟶ P + Q = 4 -- equation (1).
Product of the zeroes = c/a
⟶ PQ = 1/4 -- equation (2)
We know that,
(a + b)³ = a³ + b³ + 3ab(a + b).
⟶ (P + Q)³ = P³ + Q³ + 3PQ(P + Q)
Putting the values from equations (1) & (2) we get,
⟶ (4)³ = P³ + Q³ + 3* (1/4) * (4)
⟶ 64 = P³ + Q³ + 3
⟶ 64 - 3 = P³ + Q³
⟶ 61 = P³ + Q³
Hence, the value of P³ + Q³ is 61.
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