If P+Q = P-Q, the what will be the angle theta ??
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Let the angle between the 2 vectors P and Q be X
We know that,
P + Q = √(P² + Q² + 2PQcosX)
P - Q = √(P² + Q² - 2PQcosX)
Since P + Q = P - Q
√(P² + Q² + 2PQcosX) = √(P² + Q² - 2PQcosX)
P² + Q² + 2PQcosX = P² + Q² - 2PQcosX
2PQcosX = - 2PQcosX
2PQcosX + 2PQcosX = 0
4PQcosX = 0
cosX = 0
X = 90°
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