Question

The sum of three consecutive multiples of 11 is 363 .find this multiples
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Answer 1

Hello ❤️

Let the multiples be

x, x+11, x+22

$x + x + 11 + x + 22 = 363 \\ \\ 3x + 33 = 363 \\ \\ 3x = 363 - 33 \\ \\ 3x = 330 \\ \\ x = \frac{330}{3} \\ \\ x = 110$

The three multiples are

$x = 110 \\ \\ \\ \\ x + 11 = 110 + 11 \\ = 121 \\ \\ \\ \\ x + 22 = 110 + 22 \\ = 132$

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#BEBRAINLY

Answer 2

${\pink{\bf{\huge{\star{Smile{\star}}}}}}$

${\blue{\bf{\huge{\boxed{\boxed{110,121,132}}}}}}$

Let the numbers be,

x,x+11 and x+22

$x + x + 1</strong><strong>1</strong><strong> + x + </strong><strong>2</strong><strong>2 = 363 \\ 3x + 3</strong><strong>3</strong><strong>= 363 \\ 3x = </strong><strong>3</strong><strong>3</strong><strong>0</strong><strong> \\ x = 1</strong><strong>1</strong><strong>0$

therefore numbers are

$1</strong><strong>1</strong><strong>0</strong><strong> \\ 1</strong><strong>2</strong><strong>1</strong><strong>\\ 1</strong><strong>3</strong><strong>2</strong><strong>$

Happy Easter❤✌