if √p + √q - √r =0 then find the value of( p + Q - r)
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Answered by
2
Hello Dear !
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√p + √q - √r - 0 _____(1)
√p + √q = √r _____(2)
squaring both sides
p + q + 2√p√q = r
p + q - r = -2√p√q
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_________________________________________________________
√p + √q - √r - 0 _____(1)
√p + √q = √r _____(2)
squaring both sides
p + q + 2√p√q = r
p + q - r = -2√p√q
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Anonymous:
sorries :(
Answered by
2
√p+√q-√r =0
√p+√q = √r
Squaring on both sides,
(√p+√q)² = √r²
√p²+√q²+2(√p)(√q) = r
p+q+2√pq = r
p+q-r = -2√pq
Hope it helps
√p+√q = √r
Squaring on both sides,
(√p+√q)² = √r²
√p²+√q²+2(√p)(√q) = r
p+q+2√pq = r
p+q-r = -2√pq
Hope it helps
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