if p,q,r,s are in G.P show that p+q,q+r,r+s are also in G.P
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Step-by-step explanation:
q/p= R
q=pR
r/q=R
r=Rq=pR^2
s/r=R
s=Rr
s=R^3 p
suppose
p+q,q+r,r+s are in g.p then
q+r/p+q= K=r+s/q+r
(substitute value of q,r)
pR+R^2p/ pR +p=K
pR(1+R)/p(1+R)=K
there fore K=R
it is same for
r+s/q+r
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