Question

If p q r s t are in



a.P then the value of p-4q+6r-4s+t is

Answer 1

Answer:

-a

Step-by-step explanation:

a-4a+6a-4a+a

a+6a+a=7a

-4a-4a=-8a

7a-8a=-a

Answer 2

Answer:

0

Step-by-step explanation:

Given,

p q r s t are in  AP ( arithmetic progression )

∵ In the AP the consecutive terms are in common difference,

i.e.  q - p = r - q = s - r = t - s ------(1)

Now,

p - 4q + 6r - 4s + t

= p - q - 3q + 6r - 3s - s + t

= p - q - 3q + 6r - 3s + q - p  ( from equation (1) )

= - 3q + 6r - 3s

= -3(q+s) + 6r      ( ∵ r- q = s - r ⇒ s+q = 2r )

= -6r + 6r

= 0