Question

If (p^q)^r=^t√p^2 then. qrt=?​

Answer 1

Answer:

(P^2+Q^2+2.P.Q cos P^Q)^1/2 =P+Q

Square both sides:-

P^2+Q^2+2.P.Q cos P^Q=P^2+Q^2+2.P.Q

So,cos p^q=1

So angle between vector p and q (p^q) =0

I think this is right