Question

if p(t)=4t^4+ 5t^3-t^2+6 then p(1)=?​

Answer 1

p(1)=14

Pls mark as brainliest answer

Answer 2

Answer:

14

Step-by-step explanation:

$p(t)=4t^4+ 5t^3-t^2+6 \\ p(1)=4(1)^4+ 5(1)^3-(1)^2+6 \\ = 4 + 5 - 1 + 6 = 14$