If p(t) = t^3-1 find the value of p(1), p(-1), p(2) ,p(-2)
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Answer:
p(1)=0
p(-1)=-2
p(2)=7
p(-2)=-9
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⎟⎟ ✪✪ QUESTION ✪✪⎟⎟
ɪғ ᴘ(ᴛ) = ᴛ^3-1 ғɪɴᴅ ᴛʜᴇ ᴠᴀʟᴜᴇ ᴏғ ᴘ(1), ᴘ(-1), ᴘ(2) ,ᴘ(-2)
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⎟⎟ ✪✪ ANSWER ✪✪⎟⎟
ɢɪᴠᴇɴ ᴘᴏʟʏɴᴏᴍɪᴀʟ p ( t ) = t^3 -1
➻ p ( 1 ) = 1^3 - 1 = 1 - 1 = 0
➻ p ( -1 ) = (-1 )^3 - 1 = -1 -1 = -2
➻ p ( 2 ) = 2^3 - 1 = 8 - 1 = 7
➻ p (-2 ) = (-2 )^3 - 1 = -8 -1 = -9
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