if p(t)=t3-1, find the value s of p(1),p(-1)p(0),p(2),p(-2)
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Answer:
1. p(t)= t3-1
p(1)= (1)^3-1
p(1)= 1-1
p(1)= 0
2. p(t)= t3-1
p(-1)= (-1)^3 -1
p(-1)= -1-1
p(-1)= -2
3. p(t)=t3-1
p(0) = (0)^3 -1
p(0) = 0-1
p(0)=-1
4. p(t)=t3-1
p(2)=(2)^3 -1
p(2)= 8-1
p(2) = 7
5. p(t)=t3-1
p(-2) = (-2)^3 - 1
p(-2)= -8-1
p(-2)= -9
HOPE THIS HELP U
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