If p(t) = t³ – 1, find the values of p(1), p(–1), p(0), p(2), p(–2).
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This was very simple question.
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Solution :
Given p(t) = t³ - 1
i ) p(1) = 1³ - 1 = 1 - 1 = 0
ii ) p(-1) = ( -1 )³ - 1 = -1 - 1 = -2
iii ) p(0) = 0³ - 1 = -1
iv) p(2) = 2³ - 1 = 8 - 1 = 7
v ) p(-2) = ( -2 )³ - 1 = -8 - 1 = - 9
••••••
Given p(t) = t³ - 1
i ) p(1) = 1³ - 1 = 1 - 1 = 0
ii ) p(-1) = ( -1 )³ - 1 = -1 - 1 = -2
iii ) p(0) = 0³ - 1 = -1
iv) p(2) = 2³ - 1 = 8 - 1 = 7
v ) p(-2) = ( -2 )³ - 1 = -8 - 1 = - 9
••••••
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