if p term of an AP is c an the q term is d .what is the r term
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Nth term Tn = a + ( n-1) d so ,
a= first term
d = common diff.
Tp = a + (p-1)d = - q
= a + pd - d = -q --(1)
T(p+q) = a + ( p+q-1)d = 0
= a + pd + qd - d = 0 --(2)
equation (1) - equation (2)
= -qd = -q
= d= 1
eq(1) =
a + p - 1 = - q
=> a = -p - q +1
therefore qth term =
Tq = a + ( q-1)d
putting the value of a and d
= -p - q +1 + (q-1)
= -p -q +1 + q -1
= -p
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