If p times the ph term of an AP is equal to (2p+1
times the (2p + 1) term, then show that its
(3p + 1) term is zero.
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Answer:
Eq:-
p(a+(p-1)d)=(2p+1)(a+2pd)
=>pa+p2d-pd=2pa+4p2d+a+2pd
=>3p2d+pa+3pd+a=0
=>3pd(p+1)+a(p+1)=0
=>3pd+a=0
a(3p+1)=a+(3p+1-1)d=a+3pd
thus,3pd+a=0
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