if p(x)=2+(x/2)+x²-(x³/3), then find p(-1)
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The value of p(-1) is 17/6.
Given:
A polynomial p(x) = 2+(x/2)+x²-(x³/3).
To Find:
The value of p(-1).
Solution:
We have been given a polynomial p(x) = 2+(x/2)+x²-(x³/3).
Here the polynomial is a function of 'x'
We need to find the value of p(-1). This can be found by replacing 'x' with -1. Hence,
p(-1) = 2+(-1/2)+(-1)²-(-1³/3)
⇒ p(-1) = 2 - 1/2 + 1 + 1/3
⇒ p(-1) = 2 + 1/2 + 1/3 = 2 + 5/6 = 17/6.
Hence, the value of p(-1) = 17/6.
∴ The value of p(-1) is 17/6.
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