Math, asked by Samyra523, 9 months ago

if p(x)=2+(x/2)+x²-(x³/3), then find p(-1)

Answers

Answered by Abhilash210
0

That's may be your answer. I hope it will help you.

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Answered by halamadrid
0

The value of p(-1) is 17/6.

Given:

A polynomial p(x) = 2+(x/2)+x²-(x³/3).

To Find:

The value of p(-1).

Solution:

We have been given a polynomial p(x) = 2+(x/2)+x²-(x³/3).

Here the polynomial is a function of 'x'

We need to find the value of p(-1). This can be found by replacing 'x' with -1. Hence,

p(-1) = 2+(-1/2)+(-1)²-(-1³/3)

⇒ p(-1) = 2 - 1/2 + 1 + 1/3

⇒ p(-1) = 2 + 1/2 + 1/3 = 2 + 5/6 = 17/6.

Hence, the value of p(-1) = 17/6.

∴ The value of p(-1) is 17/6.

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