Math, asked by jaisleengrewal2379, 1 year ago

If p(x)=2x^2-3x+5 Find the value 0f p(1) and p(-2)

Answers

Answered by guranshbhatia
0

Answer:

4 and 19

Step-by-step explanation:

p(1) = 2×(1)^2-3×1+5

= 2-3+5

= 4

p(-2) = 2×(-2)^2-3×(-2)+5

= 2×4+6+5

= 8+6+5

= 19

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