If p(x)=2x^2-3x+5 Find the value 0f p(1) and p(-2)
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Answer:
4 and 19
Step-by-step explanation:
p(1) = 2×(1)^2-3×1+5
= 2-3+5
= 4
p(-2) = 2×(-2)^2-3×(-2)+5
= 2×4+6+5
= 8+6+5
= 19
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