If p(x) = 2x ^3- x^2 +3x+1 find the value of : p(-1) +p(1)/2
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Answer:
Step-by-step explanation:
p(-1)=
2(-1)^3 - (-1)^2 +3(-1) + 1 = 2(-1) - (1) -3 +1
= -2 -1-3 + 1 = -5 ans
when p(1) = 2(1)^3 _ (1)^2 + 3 (1) +1
= 2(1) - 1 +3 +1 = 2-1+3+1
=6 -1 =5 ans (bodmas rule)
p(-1) + p(1) / 2
= (-5 + 5 )/2
=(0)/2
=0 answer
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