Question

If p(x)=√2x cube-3x square 4 √2x-6, then find the value of p(√2)

Answer 1

Step-by-step explanation:

Given  

If p(x) =√2x cube - 3x square + 4√2x - 6, then find the value of p(√2)

We need to find p (√2)

So given p(x) = √2 x^3 – 3 x^2 + 4 √2 x – 6

Now putting x = √2 we get

So p (√2) = √2 x (√2)^3 – 3 (√2)^2 + 4 √2 x √2 – 6

               = 4 – 6 + 4 x 2 – 6

              = 4 – 6 + 8 – 6

              = 12 – 12

              = 0