Math, asked by sktank, 3 months ago

If P(x) = 2x² - X-1, then P(1)=

Answers

Answered by mathschandusir
0

Answer:

p(1) = 2 - 1 - 1 = 2 - 2 = 0

Answered by Anonymous
15

\huge{\underline{\underline{\sf{\blue{Given\::}}}}}

  • \sf{P(x)\:=\:2x}^{2}\:{-\:x\:1}

{ }

\huge{\underline{\underline{\sf{\blue{Find\::}}}}}

  • \sf{P(1)\:=\:?}

{ }

\huge{\underline{\underline{\sf{\blue{Solution\::}}}}}

  • \bf{P(x)\:=\:2x}^{2}\:{-\:x\:1}
  • \bf{Now,\:We\:Know\:the\:Value\:of\:x\:is\:1}

\large{\green{\sf{Putting\:the\:Value\:-}}}

{ }

\:\:\:\:\:\:\::\:\Longrightarrow\sf{P(1)\:=\:2\:\times\:{(1)}^{2}\:-\:1\:-\:1}

\:\:\:\:\:\:\::\:\Longrightarrow\sf{P(1)\:=\:2\:-\:1\:-\:1}

\:\:\:\:\:\:\::\:\Longrightarrow\sf{P(1)\:=\:2\:-\:2}

\:\:\:\:\:\:\::\:\Longrightarrow\sf{P(1)\:=\:0}

{ }

\:\:\:\:\:\:{\bold{\purple{\dag}}}\:{\underline{\sf{So,\:the\:P(1)\:is\:{\bold{\pink{\mathfrak{0}}}}}}}.

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